Storieta
English
Save & sign up

About this book

The First Six Books of the Elements of Euclid presents the foundational geometry of ancient Greece in a straightforward, proposition‑by‑proposition format. The opening pages jump straight into rigorous demonstrations, beginning with the classic “If in any triangle one side is greater than another, the angle opposite the greater side is greater than the angle opposite the lesser.” Each proposition is followed by a concise proof, a series of exercises, and occasional remarks on construction methods. The text is organized exactly as Euclid’s original work, with numbered propositions, diagrams described in the margin, and a logical progression from basic triangle inequalities to more elaborate constructions such as medians and circle intersections.

The voice is that of a meticulous ancient mathematician, rendered into English by John Casey in a literal, almost scholastic style that preserves the terse, deductive tone of the original. Readers who enjoy disciplined logical reasoning, historical approaches to mathematics, or the pleasure of working through step‑by‑step geometric arguments will find this volume rewarding. It appeals especially to students of mathematics, historians of science, and anyone who appreciates the disciplined elegance of classical Greek geometry.

Opening lines

Exercise. Prove Prop. x v i i . without producing a side. PROP. XVIII.—T h e o r e m . If in any triangle ( ABC ) one side ( AC ) be greater than another ( AB ) , the angle opposite to the greater side is grater than the angle opposite to the less. Dem. —From AC cut off AD equal to AB [ i i i ]. Join BD (Post. i . ). Now since AB is equal to AD , the triangle ABD is isosceles; therefore [ v . ] the angle ADB is equal to ABD ; but the angle ADB is greater than the angle ACB [ x v i . ]; therefore ABD is greater than ACB . Much more is the angle ABC greater than the angle ACB . Or thus: From A as centre, with the lesser side AB as radius, describe the circle BED , cutting BC in E . Join AE . Now since AB is equal to AE , the angle AEB is equal to ABE ; but AEB is greater than ACB ( x v i .); therefore ABE is greater than ACB . Exercises. 1.

Keep reading free · start reading with no account

New illustrated classics

A new classic, drawn, in your inbox.

Once or twice a month: the latest books to get full character casts, scene art, and free comic editions. No account needed.